1x^2-40x+256=0

Solution for 1x^2-40x+256=0 equation:

Simplifying
1x2 + -40x + 256 = 0

Reorder the terms:
256 + -40x + 1x2 = 0

Solving
256 + -40x + 1x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(8 + -1x)(32 + -1x) = 0

Subproblem 1
Set the factor '(8 + -1x)' equal to zero and attempt to solve:

Simplifying
8 + -1x = 0

Solving
8 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1x = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1x = 0 + -8
-1x = 0 + -8

Combine like terms: 0 + -8 = -8
-1x = -8

Divide each side by '-1'.
x = 8

Simplifying
x = 8
Subproblem 2
Set the factor '(32 + -1x)' equal to zero and attempt to solve:

Simplifying
32 + -1x = 0

Solving
32 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-32' to each side of the equation.
32 + -32 + -1x = 0 + -32

Combine like terms: 32 + -32 = 0
0 + -1x = 0 + -32
-1x = 0 + -32

Combine like terms: 0 + -32 = -32
-1x = -32

Divide each side by '-1'.
x = 32

Simplifying
x = 32
Solution
x = {8, 32}